# day/dydd 259 at 7puzzleblog.com T he Main Challenge

From the following list of numbers:

12  14  18  21  25  28  30  33  35  36  40  42  44  48  54  55  56

find the ONLY number remaining when you eliminate multiples of 3, 5 and 7. The 7puzzle Challenge

The playing board of the 7puzzle game is a 7-by-7 grid of 49 different numbers, ranging from up to 84.

The 3rd & 7th rows contain the following fourteen numbers:

4   11   13   24   25   27   30   36   42   45   66   70   77   80

What is the sum of the multiples of 4? The Factors Challenge

Which is the ONLY number below that is a factor of 259?

3      5      7      9      11      13

Today’s Hint: Use the ‘bus stop’ method of division to see which of the above numbers divide exactly into 259 ] The Mathematically Possible Challenge

Using 58 and 11 once each, with + – × ÷ available, which is the ONLY number it is possible to make from the list below?

50    51    52    53    54    55    56    57    58    59

#NumbersIn50s The Target Challenge

Can you arrive at 259 by inserting 1, 3, 5, 7 and 9 into the gaps below?

•  (◯+◯)²+√(◯+◯+◯) = 259   