**The Main Challenge**

Players must multiply two numbers together, then either add or subtract the third number to achieve your target answer of **25**, so the formula is (a×b)±c, where a b c are three UNIQUE digits from **1-9**.

One way of achieving **25** is (8×2)+9, can you find the other EIGHT ways?

[ Note: (8×2)+9 = 25 and (2×8)+9 = 25 counts as just ONE way ]

**The 7puzzle Challenge**

The playing board of **the 7puzzle game** is a 7-by-7 grid containing 49 different numbers, ranging from **2 **up to **84**.

The 3rd column contains the following seven numbers:

4 12 15 17 35 80 81

Using these seven numbers exactly once each, with + – × ÷ available to use in your calculation, can you arrive at the target number of **100**?

**T****he Factors Challenge**

**The Mathematically Possible Challenge**

Using **4**, **8** and **12 **once each, with + – × ÷ available, which are the only TWO numbers it is NOT possible to make from the list below?

8 16 24 32 40 48 56 64 72 80

#*8TimesTable*

**The Target Challenge**

Can you arrive at **360** by inserting **3**, **5**, **10**, **12** and **20** into the gaps below?

- ◯×◯×◯×◯÷◯ = 360

**Answers **can be found **here**.

**Click Paul Godding for details of online maths tuition.**