DAY 327:

Today’s Challenge

. . . is a tricky 5puzzle-style question that’s a real mouth-watering prospect for the number puzzle enthusiast.

Using the numbers 1, 2, 3, 4 and 5 once each, with + – × ÷ available, it is possible to make the vast majority of numbers from 50-100.

For example, to arrive at 50 and 51, you could do:

  • (4+3+2+1)×5 = 50,
  • [(4×32)×5]+1 = 51, and so on . . .

Continuing your calculations, what is the LOWEST number in the range 52-100 it is not possible to make.

The 7puzzle Challenge

The playing board of the 7puzzle game is a 7-by-7 grid containing 49 different numbers, ranging from up to 84.

The 3rd & 6th columns of the playing board contain the following fourteen numbers:

4    7    12    15    17    30    35    36    40    49    54    64    80    81

How many square numbers are listed above?

Make 327 Challenge

Can you arrive at 327 by inserting 3, 5, 5, 7 and 7 into the gaps below?

◯×[(◯+◯)²–◯×◯] = 327

Answers can be found here.

Click Paul Godding for details of online math tuition. Wherever you are in the world, please get in touch.

This entry was posted in 7puzzleblog.com. Bookmark the permalink.

Leave a Reply

Your email address will not be published. Required fields are marked *