**Today’s Challenge**

In this particular number puzzle, three UNIQUE digits must be used to arrive at a specified target number; today is **42**. The formula is always the same – multiply two numbers together, then either add or subtract a third number to achieve your target:

**(a×b)±c**, where a, b and c are three unique digits from 1-9.

One way to make 42 is (9×4)+6; can you find the only other two ways of making 42?

[Note: (9×4)+6 and (4×9)+6 counts as just ONE way.]

**The 7puzzle Challenge**

The playing board of **the 7puzzle game** is a 7-by-7 grid containing 49 different numbers, ranging from **2 **up to **84**.

The 5th & 6th columns of the playing board contain the following fourteen numbers:

7 8 11 14 18 25 30 36 40 44 49 54 64 84

What is the difference between the highest and lowest multiples of 4?

**Make 320 Challenge**

Can you arrive at 320 by inserting 10, 20, 30, 40 and 50 into the gaps below?

◯×◯×(◯–◯)÷◯ = 320

**Answers **can be found **here**.

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