DAY 320:

Today’s Challenge

In this particular number puzzle, three UNIQUE digits must be used to arrive at a specified target number; today is 42.  The formula is always the same – multiply two numbers together, then either add or subtract a third number to achieve your target:

  • (a×b)±c, where a, b and c are three unique digits from 1-9.

One way to make 42 is (9×4)+6; can you find the only other two ways of making 42?

[Note:  (9×4)+6 and (4×9)+6 counts as just ONE way.]

The 7puzzle Challenge

The playing board of the 7puzzle game is a 7-by-7 grid containing 49 different numbers, ranging from 2 up to 84.

The 5th & 6th columns of the playing board contain the following fourteen numbers:

7    8    11    14    18    25    30    36    40    44    49    54    64    84

What is the difference between the highest and lowest multiples of 4?

Make 320 Challenge

Can you arrive at 320 by inserting 10, 20, 30, 40 and 50 into the gaps below?

◯×◯×(◯–◯)÷◯ = 320

Answers can be found here.

Click Paul Godding for details of online math tuition. Wherever you are in the world, please get in touch.

This entry was posted in 7puzzleblog.com. Bookmark the permalink.

Leave a Reply

Your email address will not be published. Required fields are marked *