**Today’s Challenge**

By using the formula (a×b)±c, where a b and c are three unique digits from 1-9, one way of arriving at 24 is (5×3)+9, but there is only one other way of making 24 when using the above rule. Can you find it?

[Note: (5×3)+9 = 24 and (3×5)+9 = 24 counts as just ONE way.]

**The 7puzzle Challenge**

The playing board of **the 7puzzle game** is a 7-by-7 grid containing 49 different numbers, ranging from **2 **up to **84**.

The 2nd & 5th rows of the playing board contain the following fourteen numbers:

6 7 8 16 17 21 28 48 50 55 63 64 81 84

Which three pairs of numbers all have a difference of 47?

**Make 312 Challenge**

Can you arrive at 312 by inserting 2, 3, 4, 6 and 8 into the gaps below?

(◯+◯+◯)×◯×◯ = 312

**Answers **can be found **here**.

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