**The Main Challenge**

By using the formula (a×b)+c, where a b and c are three unique digits from **1-9**, one way of arriving at **24** is (5×3)+9, but can you find the only other way of making **24** when using the above rule.

**The 7puzzle Challenge**

The playing board of **the 7puzzle game** is a 7-by-7 grid containing 49 different numbers, ranging from **2 **up to **84**.

The 2nd & 5th rows contain the following fourteen numbers:

6 7 8 16 17 21 28 48 50 55 63 64 81 84

Which three pairs of numbers all have a difference of 47?

**T****he Factors Challenge**

**The Mathematically Possible Challenge**

Using **4**, **7** and **11 **once each, with + – × ÷ available, which are the only THREE numbers it is possible to make from the list below?

8 16 24 32 40 48 56 64 72 80

#*8TimesTable*

**The Target Challenge**

Can you arrive at **312** by inserting **2**, **3**, **4**, **6** and **8** into the gaps below?

- (◯+◯+◯)×◯×◯ = 312

**Answers **can be found **here**.

**Click Paul Godding for details of online maths tuition.**