DAY 312

Today’s Challenge

Three unique digits from 1-9 must be used in a particular way to arrive at a specified target number – by multiplying two of the numbers together, and then either adding or subtracting the third unique number to arrive at your target.

By using the formula (a×b)±c, where a b and c are three unique digits from 1-9, one way of arriving at 24 is (5×3)+9.  Incredibly, there is only one other way of making 24 when using the above rule. Can you find it?

[Note:  (5×3)+9 = 24 and (3×5)+9 = 24 counts as just ONE way.]

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The 7puzzle Challenge

The playing board of the 7puzzle game is a 7-by-7 grid containing 49 different numbers, ranging from 2 up to 84.

The 2nd & 5th rows of the playing board contain the following fourteen numbers:

6     7     8     16     17     21     28     48     50     55     63     64     81     84

Which three pairs of numbers all have a difference of 47?

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Answers

. . . can be found when clicking this.

7puzzleblog

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