DAY 287:

The Main Challenge

When allocating each letter of the English alphabet a numerical value as follows, A=1 B=2 C=3 . . . Z=26, calculate your answer when adding up the values of the individual letters of:

MATHEMATICALLY POSSIBLE

Take a browse at our popular strategy board game by clicking Mathematically Possible.

The 7puzzle Challenge

The playing board of the 7puzzle game is a 7-by-7 grid of 49 different numbers, ranging from up to 84.

The 4th & 7th rows contain the following fourteen numbers:

3   4   10   11   24   27   30   32   35   44   54   60   70   77

Which three pairs of numbers all have a difference of 17?

The Factors Challenge

Which is the ONLY number from the following list that is a factor of 287?

3     5     7     9     11     13     15     17

The Mathematically Possible Challenge

Using 27 and 10 once each, with + – × ÷ available, which is the ONLY number it is possible to make from the list below?

80    81    82    83    84    85    86    87    88    89

#NumbersIn80s

The Target Challenge

Can you arrive at 287 by inserting 2, 3, 4, 5 and 6 into the gaps below?

  •  ◯²×◯²×◯+◯ = 287

Answers can be found here.

Click Paul Godding for details of online maths tuition.

This entry was posted in 7puzzleblog.com. Bookmark the permalink.

Leave a Reply

Your email address will not be published. Required fields are marked *