28 November 2012: COUNTDOWN 333

Try this COUNTDOWN-style challenge similar to the maths challenges regularly seen on the Channel 4 show in the UK. There is one big difference – ALL six numbers must be used in the calculation.

Using the six numbers 2 5 5 8 8 50 once each, with + – x ÷ available, can you arrive at a target number of 333?

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10 Responses to 28 November 2012: COUNTDOWN 333

  1. Luc says:

    To get 333, you have to do 8-2 =6×50=300+5×5=25+8=333

  2. Mara says:

    I found the answer, what you do is:
    8-2=6
    6×50=300
    300+5 x 5=325
    325+8=333

  3. Winston says:

    2×50=100.
    5-8=3
    3×100=300
    5×5=25
    300+25=325+8=333

    • 7puzzle says:

      Well done, although I think you meant 8-5=3 on the 2nd line, and did you use the 5 three times???
      I did:
      (50×8) – [(8+5)x5 + 2] = 333

  4. St Lawrence Year 6 says:

    50 – 8= 42
    42 x 8= 336
    5/5 = 1
    1+2=3

    336-3 = 333

  5. Laura Mostyn says:

    I did
    8-5 = 3
    2×50=100.
    3×100=300
    5×5=25
    300+25=325+8=333

    • 7puzzle says:

      Good try Laura, but each number must only be used once each. Looking at your answer above, I think you used 5 three times.
      You did: [(8-5)x2x50]+[(5×5)+8)]=333

      This is how I did it:
      I did [50×8]–[(8+5)x5 +2] = 333

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