# 28 November 2012: COUNTDOWN 333

Try this COUNTDOWN-style challenge similar to the maths challenges regularly seen on the Channel 4 show in the UK. There is one big difference – ALL six numbers must be used in the calculation.

Using the six numbers 2 5 5 8 8 50 once each, with + – x ÷ available, can you arrive at a target number of 333?

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### 10 Responses to 28 November 2012: COUNTDOWN 333

1. Luc says:

To get 333, you have to do 8-2 =6×50=300+5×5=25+8=333

• 7puzzle says:

You too Luc, great calculations!

2. Mara says:

I found the answer, what you do is:
8-2=6
6×50=300
300+5 x 5=325
325+8=333

• 7puzzle says:

Superb work Mara, a better answer than mine.
I did (50×8) – [(8+5)x5 + 2] = 333

3. Winston says:

2×50=100.
5-8=3
3×100=300
5×5=25
300+25=325+8=333

• 7puzzle says:

Well done, although I think you meant 8-5=3 on the 2nd line, and did you use the 5 three times???
I did:
(50×8) – [(8+5)x5 + 2] = 333

4. St Lawrence Year 6 says:

50 – 8= 42
42 x 8= 336
5/5 = 1
1+2=3

336-3 = 333

• 7puzzle says:

Good work, didn’t see that way!
I did (50×8) – [(8+5)x5 + 2] = 333

5. Laura Mostyn says:

I did
8-5 = 3
2×50=100.
3×100=300
5×5=25
300+25=325+8=333

• 7puzzle says:

Good try Laura, but each number must only be used once each. Looking at your answer above, I think you used 5 three times.
You did: [(8-5)x2x50]+[(5×5)+8)]=333

This is how I did it:
I did [50×8]–[(8+5)x5 +2] = 333