Try this **COUNTDOWN**-style challenge similar to the maths challenges regularly seen on the Channel 4 show in the UK. There is one big difference – ALL six numbers must be used in the calculation.

**Using the six numbers 2 5 5 8 8 50 once each, with + – x ÷ available, can you arrive at a target number of 333?**

To get 333, you have to do 8-2 =6×50=300+5×5=25+8=333

You too Luc, great calculations!

I found the answer, what you do is:

8-2=6

6×50=300

300+5 x 5=325

325+8=333

Superb work Mara, a better answer than mine.

I did (50×8) – [(8+5)x5 + 2] = 333

2×50=100.

5-8=3

3×100=300

5×5=25

300+25=325+8=333

Well done, although I think you meant 8-5=3 on the 2nd line, and did you use the 5 three times???

I did:

(50×8) – [(8+5)x5 + 2] = 333

50 – 8= 42

42 x 8= 336

5/5 = 1

1+2=3

336-3 = 333

Good work, didn’t see that way!

I did (50×8) – [(8+5)x5 + 2] = 333

I did

8-5 = 3

2×50=100.

3×100=300

5×5=25

300+25=325+8=333

Good try Laura, but each number must only be used once each. Looking at your answer above, I think you used 5 three times.

You did: [(8-5)x2x50]+[(5×5)+8)]=333

This is how I did it:

I did [50×8]–[(8+5)x5 +2] = 333