**Today’s Challenge**

Three UNIQUE digits must be used to arrive at the target number 37.

The rule – players must multiply two numbers together, then either add or subtract the third number to achieve the target answer of 37.

Using the formula (a×b)±c, where a, b and c are three unique digits from 1-9, one way of achieving 37 is (7×5)+2, can you find the other SEVEN ways?

[Note: (7×5)+2 = 37 and (5×7)+2 = 37 counts as just ONE way.]

**The 7puzzle Challenge**

The playing board of **the 7puzzle game** is a 7-by-7 grid containing 49 different numbers, ranging from **2 **up to **84**.

The 5th & 6th rows of the playing board contain the following fourteen numbers:

5 6 7 12 16 18 20 21 33 49 50 56 81 84

From the list, which three different numbers have a sum of 100?

**Make 224 Challenge**

Can you arrive at 224 by inserting 1, 2, 3 and 4 into the gaps on each line?

- (5+◯)×◯×(◯²–◯) = 224
- (◯³÷◯)×(2×◯+◯) = 224

**Answers **can be found **here**.

**Click Paul Godding for details of online math tuition. Wherever you are in the world, please get in touch.**